新符号学 (第19/25页)

0.530612...\}{\dispystyle{\frac{26}{49}}=0.530612...\}作为朔望月零数部分的强率。运用调日法，最後得到{\dispystyle{\frac{399}{752}}\}{\dispystyle{\frac{399}{752}}\}，根据他的观测数值0.530585，首先计算d1,d2

    {\dispystyle{\begin{aligned}d_{1}&=0.530585-0.529412&=0.001173\\d_{2}&=0.530612-0.530585&=0.000027\end{aligned}}}{\dispystyle{\begin{aligned}d_{1}&=0.530585-0.529412&=0.001173\\d_{2}&=0.530612-0.530585&=0.000027\end{aligned}}}

    寻找满足以下关系的m,k值：

    {\dispystyle{\begin{aligned}{\frac{49k}{17m}}&={\frac{1173}{27}}\\{\frac{k}{m}}&={\frac{1173\times17}{49\times27}}&\approx{}15.07\ldots\end{aligned}}}{\dispystyle{\begin{aligned}{\frac{49k}{17m}}&={\frac{1173}{27}}\\{\frac{k}{m}}&={\frac{1173\times17}{